Thursday, October 3, 2019

Standardization of sodium hydroxide by ethanedioic acid solution Essay Example for Free

Standardization of sodium hydroxide by ethanedioic acid solution Essay Experiments: 1. Standardization of sodium hydroxide by ethanedioic acid solution 2. Determination of the concentration of commercial colourless vinegar Standardization of sodium hydroxide by ethanedioic acid Objective: To determine the molarity of sodium hydroxide. As the molarity of the sodium hydroxide is unknown, in order to standardize it, the concentration of the acid has to be known. Result: Titration Trial 1 2 3 4 Initial burette reading() 18. 33 8. 05 7. 52 8. 21. Final burette reading() 45. 48 36. 25 35. 79 36. 82 Volume of sodium hydroxide solution used() 27. 15(rejected) 28. 20 28. 27 28. 61 Average volume of sodium hydroxide solution used() 28. 36 Treatment for result: Molarity of the standard ethanedioic acid solution Mass of ethanedioic acid= 0. 8g Molar mass of ethanedioic acid= 2? (12+16+16+1) +2? (1+1+16) = 126 Number of mole of ethanedioic acid= 6. 35? Molarity of the ethanedioic acid= = 0. 025M Â  Molarity of the sodium hydroxide solution. Number of mole of 25. 0 ethanedioic acid= 6. 35 10 = 6. 35? Number of mole of sodium hydroxide = 6. 35 2 = 1. 27? Molarity of sodium hydroxide= 1. 27? = 0. 045M Determination of the concentration of commercial colourless vinegar Objective: The concentration of ethanoic acid in different brands of vinegar would be determined. As the compositions of vinegar in different brands are different, the highest concentration of ethanoic acid in the vinegar was said to be the best to buy. Result: Titration Trial 1 2 3 4 Initial burette reading() 5. 99 9. 28 8. 50 7. 05 Final burette reading() 20. 32 26. 22 25. 17 23. 86 Volume of sodium hydroxide solution used() 14. 33(rejected) 16. 94 16. 67 16. 80 Average volume of sodium hydroxide solution used() 16. 81 Treatment for result: * Concentration of ethanoic acid in the commercial vinegar(ShanTou) Number of mole of sodium hydroxide = 0. 045? 0. 01681 = 7. 56? ?Number of mole of ethanoic acid = 7. 56?

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