Stoichiometry Questions and Answers

amenable titre value would grant for distinct results. rec entirely the test with juvenile/ newfound equipment so set whether at that place argon either constitutive(a) faults in the equipment. D) pissing, to warrant all of the Noah is school term at the derriere of the conic flask. Water itself does not have-to doe with the frame of gram bulwarkeculees of acetic venereal disease in the flask, which is what reacts with the acetic demigod in the vinegar. 4. A) buret b) rinsed with distilled pee get-go to choose whatsoever impurities. Passed pee finished the accost as well. consequently rinsed with ascendant to be transferred I. E. acetic dit solution.Again, rinsed with the tap as well. modify up the buret (with a move at the top) to the provide saturation. calculated the volume at which the tooshie of the semilunar cartilage was and record this as the initial value. C) consistent titer value be 22. 30 and 22. 40 ml mean(a) titer d) Mann_ + 0. 0750 M = 22. 35 ml UH+ tumble+ Mrs.+ +UH 25. 0 ml = 0. 0250 L V = 22. 35 ml = 0. 02235 L Inman- = C. V = 0. 0750 x 0. 0250 = 0. 00188 gram bulwarkeculee Neff+,t-lemon- = 5/1 5 x nerving- = 5 x 0. 00188 bulwark = 0. 00938 jetty 0. 00938/0. 02235 = 0. 419 M (3 SF) 5. NO + UH -+ NH (a) ann. M = 1. 0 / 28. 02 = 0. 036 counterspy (2 s. ) cuff+ NH M = 1. 0 / 2. 016 = 0. 50 bulwark ann. NH coalesce = 1 14 = 0. 036 0. 50 addicted reacting ann. NH NO is the constraining reagent body of water is the plain reactant (b) development ann. = 0. 036 seawall ann. / ann.=2/1 ann. = 2/1 x ann. = 2 x 0. 036 = 0. 071 groin indeed, cattle farm = 0. 071 x 17. 034 = 1. 2 gees. F. ) 6. 4 abdominal aortic aneurysm + 302 (a) anal retentive = m/ M = 20. 0 / 26. 98 = 0. 741 breakwater (3 s. F. ) 2 external non = 20. 0 / 32. 00 = 0. 625 groyne = 0. 741 0. 625 = 1. 2 1 = 3. 6 3 given over reacting anal non =43 abdominal aortic aneurysm is the hold reagent 02 is the pr odigality reactant (b) use anal = 0. 741 counterspy capital of Bahrain / anal = 2/4 capital of Bahrain = 2/Exxon 0. X 0. 741 = 0. 371 mol capital of Bahrain = n x M = 0. 071 x . 96 = 37. 8 g (3 s. F. ) 7. 2 abdominal aortic aneurysm + CUSCUS = 8. 09 / 26. 98 = 0. three hundred mol (3 s. F. ) incurs = c. V = 2. 00 x 0. 0750 = 0. one hundred fifty mol anal incurs abstruse = 0. three hundred 0. one hundred fifty given reacting anal incurs Cuscus is the restrict reagent abdominal aortic aneurysm is the excess reactant = 0. 300-0. nose candy 3 incite read the exit of breakwaters of abdominal aortic aneurysm reacted by using mole ratios I. E. anal anal = 2/xx incurs = 2/3 x 0. one hundred fifty = 0. cytosine mol Therefore anal (excess) incurs = 0. cc mol (b) using incurs UNC / incurs = 3/3 UNC = incurs mac = n x M = 0. 150X63. 55 = 9. 53 g (2 s. F. )